Problems on Ages
1. Six years ago Jose was twice as old as Joseph of the ratio of their present age is 9 : 5 respectively, what is the difference between their present ages? [Bank PO 2000]
(a) 24
(b) 30
(c) 50
(d) none of these
Answer: (a)
Explanation:
Let their present ages be 9x and 5x. six years ago,
(9x-6)=2(5x-6) => x=6
The difference between their present ages = 9x-5x=4×6=24 years
2. Father’s age is 5 yrs more than mother’s age & mother’s age is 3 times of daughter’s age. The present age of daughter is 10 yrs. What was the age of father at daughter’s birth?
(a) 20 yrs
(b) 22 yrs
(c) 25 yrs
(d) 28 yrs
Answer: (c)
Explanation:
Present age of daughter= 10yrs
Mother= 10 ×3= 30yrs
Father= 30+5= 35yrs
So, father’s age while 10 yrs ago was 25 years.
3. 15 years hence a man will be 4 times as old as he was 15 years ago, His present age is?
(a) 15
(b) 20
(c) 25
(d) 30
Answer: (c)
Explanation:
Let us take present age of man is x years.
15+x=4(x-15)
15+x=4x-60
3x=75
x=25years
4. Sachin is elder than Rohit by 6 years. If their ages are in the ratio of 6:8, how old is Sachin?
(a) 6 yrs
(b) 8 yrs
(c) 10 yrs
(d) 18 yrs
Answer: (d)
Explanation:
Let Sachin age be x, Rohit age be x-6
8x= 6x-36
x= 18x
Sachin age= 18 yrs, Rohit age= 12 yrs
5. Present age ratio of x, y is 6:8, 7 years hence, the ages become 4:5. What is x’s present age?
(a) 18
(b) 20
(c) 21
(d) 25
Answer: (c)
Explanation:
After 7 years, (6m+7)/(8m+7)=4/5
30m+35=32m+28
2m=7
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